Case Study: MapReduce




Plane




















Implementation

{-@ reflect mapReduce @-} mapReduce :: Int -> (List a -> b) -> (b -> b -> b) -> List a -> b mapReduce n f op is = reduce op (f N) (map f (chunk n is)) {-@ reflect reduce @-} reduce :: (a -> a -> a) -> a -> List a -> a reduce op b N = b reduce op b (C x xs) = op x (reduce op b xs) {-@ reflect map @-} {-@ map :: (a -> b) -> xs:List a -> {v:List b | llen v == llen xs } @-} map _ N = N map f (C x xs) = f x `C` map f xs {-@ reflect chunk @-} chunk :: Int -> List a -> List (List a)




















Use Case: Summing List

{-@ reflect sum @-} sum :: List Int -> Int sum N = 0 sum (C x xs) = x `plus` sum xs {-@ reflect plus @-} plus :: Int -> Int -> Int plus x y = x + y {-@ reflect psum @-} psum :: Int -> List Int -> Int psum n is = mapReduce n sum plus is

Question: Is psum equivalent to sum?


















Proving Code Equivalence

{-@ sumEq :: n:Int -> is:List Int -> { sum is == psum n is } @-} sumEq n is = psum n is ==. mapReduce n sum plus is ==. sum is ? mRTheorem n sum plus sumRightId sumDistr is *** QED {-@ sumDistr :: xs:List Int -> ys:List Int -> {sum (xs ++ ys) == plus (sum xs) (sum ys)} @-} {-@ sumRightId :: xs:List Int -> {plus (sum xs) (sum N) == sum xs} @-}




















Sum relevant Proofs

  • Right Identity
sumRightId xs = plus (sum xs) (sum N) ==. sum xs + 0 ==. sum xs *** QED
  • Distribution
sumDistr N ys = sum (N ++ ys) ==. sum ys ==. plus 0 (sum ys) ==. plus (sum N) (sum ys) *** QED sumDistr (C x xs) ys = sum ((C x xs) ++ ys) ==. sum (C x (xs ++ ys)) ==. x `plus` (sum (xs ++ ys)) ? sumDistr xs ys ==. x `plus` (plus (sum xs) (sum ys)) ==. x + (sum xs + sum ys) ==. ((x + sum xs) + sum ys) ==. ((x `plus` sum xs) `plus` sum ys) ==. sum (C x xs) `plus` sum ys *** QED




















Map Reduce Equivalence

{-@ mRTheorem :: n:Int -> f:(List a -> b) -> op:(b -> b -> b) -> rightId:(xs:List a -> {op (f xs) (f N) == f xs } ) -> distrib:(xs:List a -> ys:List a -> {f (xs ++ ys) == op (f xs) (f ys)} ) -> is:List a -> { mapReduce n f op is == f is } / [llen is] @-} mRTheorem n f op rightId _ N = mapReduce n f op N ==. reduce op (f N) (map f (chunk n N)) ==. reduce op (f N) (map f (C N N)) ==. reduce op (f N) (f N `C` map f N ) ==. reduce op (f N) (f N `C` N) ==. op (f N) (reduce op (f N) N) ==. op (f N) (f N) ? rightId N ==. f N *** QED mRTheorem n f op rightId _ is@(C _ _) | n <= 1 || llen is <= n = mapReduce n f op is ==. reduce op (f N) (map f (chunk n is)) ==. reduce op (f N) (map f (C is N)) ==. reduce op (f N) (f is `C` map f N) ==. reduce op (f N) (f is `C` N) ==. op (f is) (reduce op (f N) N) ==. op (f is) (f N) ==. f is ? rightId is *** QED mRTheorem n f op rightId distrib is = mapReduce n f op is ==. reduce op (f N) (map f (chunk n is)) ==. reduce op (f N) (map f (C (take n is) (chunk n (drop n is)))) ==. reduce op (f N) (C (f (take n is)) (map f (chunk n (drop n is)))) ==. op (f (take n is)) (reduce op (f N) (map f (chunk n (drop n is)))) ==. op (f (take n is)) (mapReduce n f op (drop n is)) ==. op (f (take n is)) (f (drop n is)) ? mRTheorem n f op rightId distrib (drop n is) ==. f ((take n is) ++ (drop n is)) ? distrib (take n is) (drop n is) ==. f is ? appendTakeDrop n is *** QED




















Append of Take and Drop

{-@ appendTakeDrop :: i:Nat -> xs:{List a | i <= llen xs} -> {xs == (take i xs) ++ (drop i xs) } @-} appendTakeDrop i N = (take i N) ++ (drop i N) ==. N ++ N ==. N *** QED appendTakeDrop i (C x xs) | i == 0 = (take 0 (C x xs)) ++ (drop 0 (C x xs)) ==. N ++ (C x xs) ==. C x xs *** QED | otherwise = (take i (C x xs)) ++ (drop i (C x xs)) ==. (C x (take (i-1) xs)) ++ (drop (i-1) xs) ==. C x ( (take (i-1) xs) ++ (drop (i-1) xs)) ==. C x xs ? appendTakeDrop (i-1) xs *** QED




















List Definition

Built-in Lists are not supported for now.

(So does imports...)

{-@ data List [llen] a = N | C {lhead :: a, ltail :: List a} @-} data List a = N | C a (List a) {-@ measure llen @-} {-@ llen :: List a -> Nat @-} llen N = 0 llen (C _ xs) = 1 + llen xs




















List Manipulation

{-@ chunk :: i:Int -> xs:List a -> {v:List (List a) | if (i <= 1 || llen xs <= i) then (llen v == 1) else (llen v < llen xs) } / [llen xs] @-} chunk i xs | i <= 1 = C xs N | llen xs <= i = C xs N | otherwise = C (take i xs) (chunk i (drop i xs)) {-@ reflect drop @-} {-@ drop :: i:Nat -> xs:{List a | i <= llen xs } -> {v:List a | llen v == llen xs - i } @-} drop i N = N drop i (C x xs) | i == 0 = C x xs | otherwise = drop (i-1) xs {-@ reflect take @-} {-@ take :: i:Nat -> xs:{List a | i <= llen xs } -> {v:List a | llen v == i} @-} take i N = N take i (C x xs) | i == 0 = N | otherwise = C x (take (i-1) xs) {-@ reflect ++ @-} N ++ ys = ys (C x xs) ++ ys = x `C` (xs ++ ys)



















Recap



  1. Refinements: Types + Predicates
  2. Automation: SMT Implication
  3. Measures: Specify Properties of Data
  4. Termination: Semantic Termination Checking
  5. Reflection: Allow Haskell functions in Logic!
  6. Case Study: Prove Program Equivalence












Thank You!


cabal install liquidhaskell


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Recap



  • Refinement Reflection: Allow Haskell functions in Logic
  • Case Study: Prove Program Equivalence



Prove crucial properties for Haskell in Haskell!


where Haskell = a general purspose programming language.